The perimeter of rectangle is 36 cm what will be the length and breadth of the rectangle whose area is maximum
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Perimeter =36 cm
2(l+b) =36
l+b = 18
l = 18-b .... (i)
Area = 6 cm²
l × b = 6
(18 - b) ×b =6 ...... (from (i))
18b-b² =6
So - b²+18b-6 =0 ....... (ii)
Solve the quadratic equation (ii)
2(l+b) =36
l+b = 18
l = 18-b .... (i)
Area = 6 cm²
l × b = 6
(18 - b) ×b =6 ...... (from (i))
18b-b² =6
So - b²+18b-6 =0 ....... (ii)
Solve the quadratic equation (ii)
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