Question

The perimeter of rectangle is 44.The length is 5 less than double the width.Find the width of the rectangle.

Answer 1

Answer:

length = 13 metres

breadth = 9 metresgiven

perimeter of rectangle = 44 metres

perimeter of a rectangle = 2 (length+breadth)

let the width be X

then,

length = 2X-5

according to the question,

2(2X-5+X) = 44

2(3X-5) = 44

6X-10 = 44

6X = 44+10

6X = 54X = 54/6

X = 9

width=X= 9 metres

length = 2X-5 = 2x9-5= 18-5= 13 metres

check

2 (13+9)= 44

2(22) = 44

hence checked

additional work:

area of a rectangle = lengthxbreadth

area of the rectangle = 13×9

area of the rectangle = 117 metres²