the perimeter of rectangle is 50 cm the length is 5 cm more than its breadth find the length and breadth of a rectangle
Answers
Answered by
17
Hello friend
Perimeter of a rectangle = 2(l+b)
50=2(l+b)
Let the breadth(b) be x
So the length(l) will be x+5
50=2(x+5+x)
25=2x+5
2x=25-5
2x=20
x=10
Length is x+5=10+5=15
Breadth is x=10cm
Perimeter of a rectangle = 2(l+b)
50=2(l+b)
Let the breadth(b) be x
So the length(l) will be x+5
50=2(x+5+x)
25=2x+5
2x=25-5
2x=20
x=10
Length is x+5=10+5=15
Breadth is x=10cm
Answered by
33
hey
perimeter=50
ATQ
length=5+breadth
2(l+b)=50
2(5+b+b)=50
2(5+2b)=50
10+4b=50
4b=40
b=10
l=5+b
l=5+10
l=15
so length and breadth are 10 and 15
hope u understand ^_^
perimeter=50
ATQ
length=5+breadth
2(l+b)=50
2(5+b+b)=50
2(5+2b)=50
10+4b=50
4b=40
b=10
l=5+b
l=5+10
l=15
so length and breadth are 10 and 15
hope u understand ^_^
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