Question

the perimeter of rectangle is 54 cm .The breath of reactangle less than its length by 3 .Find the length and breadth of rectangle​

Answer 1

Step-by-step explanation:

Let length of rectangle=lcm

breadth of rectangle= bcm

Given length is 3 times its breadth

i.e. l= 3×b

Perimeter of the rectangle= 120 cm

i.e.2×( l+ b)=120

2×(3×b+ b)=120

2×(4×b)=120

8×b=120

b= 15 cm

Answer 2

Given :

• Breadth of Rectangle is less than its length by 3 .
• Perimeter of Rectangle is 54 cm .

To Find :

• Length and Breadth of Rectangle .

Solution :

$\longmapsto\tt{Let\:Length\:of\:Rectangle\:be=x}$

As given that Breadth of Rectangle is less than its length by 3 . So ,

$\longmapsto\tt{Breadth=x-3}$

Using Formula :

$\longmapsto\tt\boxed{Perimeter\:of\:Rectangle=2(l+b)}$

Putting Values :

$\longmapsto\tt{54=2(x+x-3)}$

$\longmapsto\tt{\cancel\dfrac{54}{2}=2x-3}$

$\longmapsto\tt{27=2x-3}$

$\longmapsto\tt{27+3=2x}$

$\longmapsto\tt{30=2x}$

$\longmapsto\tt{x=\cancel\dfrac{30}{2}}$

$\longmapsto\tt\bf{x=15}$

Value of x is 15 ..

Therefore :

$\longmapsto\tt\bf{Length\:of\:Rectangle=15\:cm}$

$\longmapsto\tt{Breadth\:of\:Rectangle=15-3}$

$\longmapsto\tt\bf{12\:cm}$