The perimeter of rectangle is 72 m.its breadth is 10m less than its length.find the dimensions of the rectangle.
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perimeter of a rectangle=2(length+breadth)
let the length of the given rectangle be x metres
then it's breadth will be (x-10)metres
perimeter=2[x+(x-10)]
72 = 2(x+x-10)
72 =2(2x-10)
72. =4x-20
72+20=4x
92=4x
92/4=x
x=23metres
the length of the given rectangle is 23metres
and it's breadth will be (x-10)=23-10
=13metres
let the length of the given rectangle be x metres
then it's breadth will be (x-10)metres
perimeter=2[x+(x-10)]
72 = 2(x+x-10)
72 =2(2x-10)
72. =4x-20
72+20=4x
92=4x
92/4=x
x=23metres
the length of the given rectangle is 23metres
and it's breadth will be (x-10)=23-10
=13metres
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