Question

the perimeter of rectangle is 75cm its length is 11/4 times its breadth. Find the length and breadth of the rectangle. ​

Answer 1

Answer:

GivEn:

Perimeter of a Rectangle = 75 cm

Length of Rectangle is \sf \dfrac{11}{4}

4

11

times it's breadth.

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To find:

Length and breadth of Rectangle.

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SoluTion:

★ Let's Breadth of Rectangle be b.

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Given that,

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Length of Rectangle is \sf \dfrac{11}{4}

4

11

times it's breadth.

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:\implies\sf Length = \dfrac{11}{4}b:⟹Length=

4

11

b

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So, As we know that,

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\star\;{\boxed{\sf{\purple{Perimeter\;of\; Rectangle = 2(l + b)}}}}⋆

PerimeterofRectangle=2(l+b)

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\small\sf\;\;\;\; \underline{Put\;the\;given\;values\;:}

Putthegivenvalues:

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:\implies\sf 75 = 2 \bigg( \dfrac{11}{4}b + b \bigg):⟹75=2(

4

11

b+b)

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:\implies\sf 75 = 2 \bigg( \dfrac{11b + 4b}{4} \bigg):⟹75=2(

4

11b+4b

)

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:\implies\sf 75 = \cancel{2} \times \dfrac{15b}{ \cancel{4}}:⟹75=

2

×

4

15b

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:\implies\sf 75 = \dfrac{15b}{2}:⟹75=

2

15b

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:\implies\sf 75 \times 2 = 15b:⟹75×2=15b

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:\implies\sf 150 = 15b:⟹150=15b

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:\implies\sf b = \cancel{ \dfrac{150}{15}}:⟹b=

15

150

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:\implies{\underline{\boxed{\sf{\pink{Breadth\;(b) = 10\;cm}}}}}\;\bigstar:⟹

Breadth(b)=10cm

★

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★ Now, Put the value of b in,

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:\implies\sf Length = \dfrac{11}{4} \times 10:⟹Length=

4

11

×10

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:\implies\sf Length = \dfrac{110}{4}:⟹Length=

4

110

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:\implies{\underline{\boxed{\sf{\blue{Length = 27.5\;cm}}}}}\;\bigstar:⟹

Length=27.5cm

★