Question

the perimeter of rectangle is 98cm and it's breath is 9cm .find length and lenght of diogonal​

Answer 1

Answer:

let the lenght of rectangle be x

perimeter= 2(l+b)

2(x+9)=98

2x+18=98

2x=98-18

2x=80

x=80/2

x=40

length = 40

Answer 2

• Here, Perimeter of rectangle = 98 cm
• Breath of rectangle = 9 cm
• So, we know that perimeter of rectangle = 2(l+b)
• 98 = 2(l+9)
• l+9 = 98/2
• length = 49-9
• length = 40cm
• By paythagores theorem,
• (length of diagonal)^2 = (length) ^2+(breath)^2
• length of diagonal = √ (40)^2 + (9)^2
• = √ 1600+81
• = √ 1681
• length of diagonal = 41 cm