Math, asked by Jyotimand, 11 months ago

The perimeter of rectangle is equal to the perimeter of square with side 14cm. If the breadth of rectangle is 9cm. Find its length

Answers

Answered by TRISHNADEVI
3

 \huge{ \underline{ \overline{ \mid{ \mathfrak{ \purple{ \:   \: SOLUTION \:  \: } \mid}}}}}

FORMULA USED

 \boxed{ \bold {\red{ \rightsquigarrow : Perimeter \:  \:  of  \:  \: a  \:  \: square = 4 \times side}}} \\  \\  \boxed{ \bold{ \red{ \rightsquigarrow:  Perimeter  \:  \: of  \:  \: a \:  \:  rectangle = 2 (length + breadth)}}}

 \underline{ \mathfrak{ \: We  \:  \: have \:  \:  to \:  \:  find : \mapsto}} \\  \\  \text{Length of the rectangle = ? } \\  \\   \underline{\mathfrak{ \: Given, \: }} \\  \\   \:  \: \mathtt{The  \:  \: side  \:  \: of \:  \:  the \:  \:  square, a = 14 cm}  \\  \\  \mathtt{\therefore  \: Perimeter \:  \:  of \:  \:  the  \:  \: square = 4a } \\  \\   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \mathtt{= (4 \times 14) cm } \\   \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \mathtt{= 56 \:  cm}</p><p>

 \mathfrak{Also,} \\  \:  \:  \:  \:  \:  \:  \underline{ \mathfrak{Given  \:  \: that,}} \\  \\   \:  \:  \:  \:  \:  \:  \:  \: \text{Perimeter of the rectangle is equal to the} \\  \text{ perimeter of the square.} \\  \\ \mathfrak{And,} \\  \\  \text{Breadth of the rectangle, b = 9 cm} \\  \\  \underline{ \mathfrak{Suppose,}} \\  \\   \:  \:  \:  \:  \:  \:  \: \text{Length of the rectangle = l}

 \underline{ \bold{ \:  \: A.T.Q., \:  \: }} \\  \\   \:  \:  \:  \:  \:  \:  \:  \: \mathtt{2 (l + b) = 4a} \\  \\  \mathtt{ \Longrightarrow \: 2(l + 9) = 56 } \\  \\ \mathtt{ \Longrightarrow \:2 \: l + 18 = 56 } \\  \\ \mathtt{ \Longrightarrow \: 2 \: l = 56 - 18} \\  \\ \mathtt{ \Longrightarrow \: 2 \: l = 38} \\  \\ \mathtt{ \Longrightarrow \:l =  \frac{38}{2}  } \\  \\  \:  \:  \: \mathtt{ \therefore \: \underline{ \:  l = 19 \: }} \\  \\  \\  \mathtt{ \underline{ \:   : \rightsquigarrow : } \:  \: Length \:  \: of \:  \: the \:  \: rectangle = 19 \: cm}

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