Question

The perimeter of rectangle is numerically equal to its are .if the width of rectangle is11/2cm than it's length is

Answer 1

Hii...

let length be l and breadth be b

according to condition,

2(l+b)=l*b

2(l+11/2)=l*11/2

2l+11=l*11/2

11=11l/2-2l

11=7l/2

22=7l

l=22/7


so,

length is 22/7cm

Answer 2

$\textbf{Perimeter of rectangle = 2(l+b)}$

Given , breadth= 11/2 cm

Perimeter of rectangle
$= 2( l + \frac{11}{2} )$

$= 2( \frac{2l + 11 }{2} )$

$= \cancel {2}( \frac{2l \: + 11 }{ \cancel 2} )$

=(2l +11 ) cm

$\textbf{Area of rectangle = length \times breadth}$

$= l \times \frac{11}{2}$

$= \frac{11l }{2} cm {}^{2}$

A/Q

Perimeter= Area

So,

$2l \: + 11 = \frac{11 \: l}{2}$

2(2l+11) =11 l

4l + 22 = 11 l

22 =11 l -4l

22 = 7 l

22/7 = l

$\textbf{So the length is 22/7 cm}$

$\huge{\textbf{Hope it helps}}$