Question

the perimeter of rectangle whose length is 60 cm and diagonol is 61 cm​

Answer 1

Answer:

242

Step-by-step explanation:

2(l + b)

2(60+61)

2(121)

242

Answer 2

Rectangle ABCD is consist two triangle.
Let triangle BCD has two sides equal AD=CD=60cm and AC=61cm
In ΔABC,
⟹(AC)
2
=(AB)
2
+(BC)
2

⟹(61)
2
=(60)
2
+(BC)
2

⟹(BC)
2
=3721−3600
⟹BC=
121
​

⟹BC=11cm
Hence, perimeter of the rectangle ABCD=25(AB+BC)
⟹2(60+11)
⟹2(71)
⟹142cm