Math, asked by maaz131126, 4 months ago

The perimeter of rectangle ,whose length is 60 metre and its diagonal is 61 meter ,is; ​

Answers

Answered by Anonymous
4

Answer:

Rectangle ABCD is consist two triangle.

Let triangle BCD has two sides equal AD=CD=60cm and AC=61cm

In ΔABC,

⟹(AC)

2

=(AB)

2

+(BC)

2

⟹(61)

2

=(60)

2

+(BC)

2

⟹(BC)

2

=3721−3600

⟹BC=

121

⟹BC=11cm

Hence, perimeter of the rectangle ABCD=25(AB+BC)

⟹2(60+11)

⟹2(71)

⟹142cm

Attachments:
Answered by akankshakamble6
2

Answer:

Rectangle ABCD is consist two triangle.

Let triangle BCD has two sides equal AD=CD=60cm and AC=61cm

In ΔABC,

⟹(AC) ^2 =(AB) ^2+(BC) ^2

⟹(61) ^2 =(60) ^2 +(BC) ^2

⟹(BC)^ 2=3721−3600

⟹BC=√121

⟹BC=11cm

Hence, perimeter of the rectangle ABCD=25(AB+BC)

⟹2(60+11)

⟹2(71)

⟹142cm

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