Question

the perimeter of rectangle with sides (6a+ b )and( a -b- C) is​

Answer 1

Answer:

The perimeter of rectangle is (14a-2c).

Step-by-step explanation:

Perimeter of the rectangle = 2(l+b)

= 2{(6a+b) + (a-b-c)}

= 2(6a+b+a-b-c)

= 2(7a-c)

= 14a-2c

Answer 2

Answer:

14a-2c is the peimeter of rectangle

Step-by-step explanation:

perimeter of rectangle=2 (l + b)

=2[(6a+b) +(a-b-c) ]

=2[7a-c]

=14a-2c

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