Question

the perimeter of rectangular blackboard is 220 cm It is 70 cm long find the width of the blackboard


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Answer 1

Answer :

›»› The width of the rectangular blackboard is 40 cm.

Given :

• The perimeter of rectangular blackboard is 220 cm It is 70 cm long.

To find :

• The width of the blackboard.

Solution :

Let us assume that, the width of the rectangular blackboard is x cm.

As we know that

→ Perimeter of rectangle = 2(length * width)

→ 220 = 2(70 + x)

→ 220 = 2 * 70 + 2 * x

→ 220 = 140 + 2 * x

→ 220 = 140 + 2x

→ 220 - 140 = 2x

→ 80 = 2x

→ x = 80 ÷ 2

→ x = 40

Hence, the width of the rectangular blackboard is 40 cm.

Verification :

→ Perimeter of rectangle = 2(length * width)

→ 220 = 2(70 + 40)

→ 220 = 2 * 70 + 2 * 40

→ 220 = 140 + 2 * 40

→ 220 = 140 + 80

→ 220 = 220

Here, LHS = RHS

Hence Verified !

Answer 2

Answer:

perimeter of rectangle = 2( l + b )

220cm=2(70+x)

220cm=140+2x

220cm-140= 2x

80cm=2x

40=x

perimeter=2( l+b)

perimeter=2(70+40)

220cm=140 +80

Step-by-step explanation:

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