The perimeter of rectangular field exceeds its width by 6m find the dimensions
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Let the breadth of the rectangle be x m
This length of the rectangle = x + 6 m
We know Perimeter = 2 (length + breadth)
128 = 2 (x + 6 + x)
128 = 2 (2x + 6)
128 = 4x + 12
4x + 12 = 128
4x = 128 - 12
4x = 116
x = 116/4
x = 29 m
The breadth of the rectangle is 29 m
The length x + 6 = 29 + 6 = 35 m
Answer : the length of rectangle is 35 m and breadth of the rectangle is 29 m
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