Question

the perimeter of rectangular field is 196 meters. It's length is 2m more than thrice it's breadth. What are the length and breadth of the field?​

Answer 1

Given:-

☆Perimeter of the rectangular field=196m

☆Length of the field is 2m more than thrice it's breadth.

To find:-

☆Length and breadth of the field

Solution:-

=>Let the breadth of the field be x m

=>Thus,length of the field=(3x+2)m

We know that,perimeter of a rectangle:-

=>2(length+breadth)

Now:-

=>2(x+3x+2)=196

=>2(4x+2)=196

=>8x+4=196

=>8x=196-4

=>8x=192

=>x=192/8

=>x=24

Thus:-

•Breadth of the field = 24m.

•Length of the field=(3×24+2)=74m.

Answer 2

ANSWER✔

$\large\underline\bold{GIVEN,}$

$\sf\dashrightarrow perimeter\:of\:field\:is\:196m$

$\sf\dashrightarrow let\:breadth\:kf\:a\:rectangle\:be\:x\:m$

$\sf\therefore length\:is\:2m\:more\:than\:thrice\:of\:its\:breadth$

$\large\underline\bold{TO\:FIND,}$

$\sf\large\dashrightarrow length\:and\:breadth\:of\:rectangle\:field$

✯FORMULA IN USE,

$\large{\boxed{\bf{ \star\:\: PERIMETER\:OF\:RECTANGLE= 2(L+B) \:\: \star}}}$

$\large\underline\bold{SOLUTION,}$

$\sf\therefore 196=2 \times \bigg( x +(3x+2) \bigg)$

$\sf\implies 196=2 \times \bigg( 4x+2\bigg)$

$\sf\implies 196= 8x+4$

$\sf\implies 196-4=8x$

$\sf\implies 192= 8x$

$\sf\implies x=\dfrac{192}{8}$

$\sf\implies x=\cancel \dfrac{192}{8}$

$\sf\implies x= 24m$

$\large{\boxed{\bf{ \star\:\:x=24m \:\: \star}}}$

$\sf\large\therefore \:the\:breadth\:of\:a\:rectangular\:field\:is\:24m$

HEIGHT OF THE RECTANGULAR FIELD IS,

$\sf\therefore HEIGHT= (3x+2)m$

$\sf\therefore x= 24$

$\sf\implies 3(24)+2$

$\sf\implies 72+2$

$\sf\implies 74m$

$\large{\boxed{\bf{ \star\:\: height\:of\: rectangular\:field\:=74m\:\: \star}}}$

$\large\underline\bold{HEIGHT\:OF\:A\: RECTANGULAR\: FIELD\:IS\:74m}$

$\large\underline\bold{BREADTH\:OF\: RECTANGLE\:IS\:24m}$

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