Question

The perimeter of rectangular field is 28 cm and its area is 48 cm^2. Find its length and breadth​

Answer 1

The perimeter of rectangular field is 28 cm and its area is 48 cm^2. Find its length and breadth.

Given,

Perimeter = 28

Area = 48cm

Perimeter = 28

2(1 + b) 28

L + b= 14 ----» (i)

b - l

Area = 48

L × b=48

Putting the value of b

L (14 - L) = 48

14L - L²= 48

L² - 14L + 48 = 0

L² - 8L - 6L + 48 = 0

L(L - 8) -6(L - 8) = 0

(L - 6)(L - 8) = 0

Therefore L = 8 , 6

Here we can take any value of l because both are positive number

Putting the value of L= 8 in 2

L × b 48

8 × b 48

b = 48/8

b = 6

Hence,

Length of rectangle = 8

Breadth of rectangle = 6

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