Question

the perimeter of rectangular field is28cm and it's area is 48cm². find it's length and breadth​

Answer 1

Answer:

Length = 8cm Breadth =6cm

Step-by-step explanation:

As we know that the perimeter of rectangular field = 28 cm

And

Area = 48 cm²

so

2(l+b) = 28 cm

l+b = 28÷2= 14 cm

and area of rectangle is l×b =48 cm²

so now

l+b = 14 cm

l×b =48 cm

so by this way we have to find the thing which gave us 14 cm on adding and 48 on multiplying .

8+6 = 14 cm

8×6 = 48cm²

(hope it's help you )

Answer 2

Given:-

• Perimeter of Rectangular Field = 28cm

• Area of Rectangular Field = 48cm²

To Find:-

• It's Length and Breadth

Formula used:-

• Area of rectangle = L × B

• Perimeter of rectangle = 2(L + B)

Solution:-

Firstly,

Perimeter of rectangle = 2(L + B)

$⟹28 = 2(L + B)$

$⟹L + B=14$

$⟹L =14-B$ ____ {1}

Now,

Area of rectangle = L × B

$⟹48 = L × B$

Putting the value of L in it,

$⟹48 = (14-B) × B$

$⟹48 = 14B-B²$

$⟹B²-14B+48=0$

By Middle term split,

$⟹B²-(8+6)B+48=0$

$⟹B²-8B-6B+48=0$

$⟹B(B-8)-6(B-8)=0$

$⟹(B-8)(B-6)=0$

$⟹B-8=0 \: or\: B-6=0$

$⟹B=8 \: or\: B=6$

Putting values in {1},

If B = 8cm

$⟹L =14-8$

$⟹L =6cm$

If B = 6cm

$⟹L =14-6$

$⟹L =8cm$

Hence, The Length and Breadth of the rectangular field is either 8cm and 6cm respectively or 6cm and 8cm respectively.

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