Question

the perimeter of rectangular greeting card is 56 CM. the ratio of length to its breadth is 4 : 3. find the Area of the greeting card?

Answer 1

perimeter = 2(l + b) = 56 cm

56 = 2 ( 4x + 3x )

56 = 2 × 7x

56 = 14x

x = 56 / 14 = 4

4x = 4×4 = 16

3x = 3×4 = 12

area = l×b sq.units

= 16 × 12 = 192 cm^2


hope it helps

Answer 2

$\textbf{\underline{\underline{Answer :-}}}$

The area of the Rectangle is 192 cm²

$\textbf{\underline{\underline{Explanation :-}}}$

Given :

Perimeter of Rectangle = 56 cm

Ratio = 4 : 3

To find :

The area of the Rectangle

Solution :

Consider the Length as 4x

Consider the Breadth as 3x

$\star$ As we know :

$\boxed{\sf{Perimeter = 2(Length + Breadth)}}$

$\sf{\implies}2(4x + 3x) = 56$

$\sf{\implies}8x + 6x = 56$

$\sf{\implies}14x = 56$

$\sf{\implies}x = \dfrac{56}{14} \\ \\ \sf{\implies}x = 4$

Value of 4x

$\sf{\implies}$ 4 × 4

$\sf{\implies}$ 16

Length = 16 cm

Value of 3x

$\sf{\implies}$ 3 × 4

$\sf{\implies}$ 12

Breadth = 12 cm

$\star$ Area of Rectangle

$\star$ As we know :-

$\boxed{\sf{Area = Length \times Breadth}}$

$\sf{\implies}12 \times 16$

$\sf{\implies}192$

$\sf{\implies}192 \: {cm}^{2}$

$\therefore$ The area of the Rectangle is 192 cm²