The perimeter of regular octagon with length of the side as 5cm is
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the perimeter is 40
since octagon has 8 sides,and a regular one...
8×5=40
hope it helps...
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QUESTION:-
The perimeter of regular octagon with length of the side as 5cm is
Answer:
Step-by-step explanation:
Let ABCDEFGH. is a regular octagon whose. center is O. In isosceles ∆
OAB. OA=OB , AB= 5 cm. and angle AOB = 45°. draw OP perpendicular
on AB
In right triangle APO :-
AP=AB/2=5/2=2.5. cm. and angle AOP=45/2=22.5°
AP/OP=tan 22.5°
2.5/OP = 0.4142
OP =2.5/0.4142 = 6.0357 cms.
Area of triangle OAB = ( AB ×OP)/2 = ( 5 ×6.0357)/2
Area of regular octagon ABCDEFGH =8×area of ∆ OAB.
=8×(5×6.0357)/2
=20×6.0357
= 120.714O sq. cm
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