the perimeter of rhombus is 100 CM and one of it, s diagonal is 48 CM find the other diagonal and the area of perimeter?
Answers
ANSWER:-
Given:
•The perimeter of rhombus is 100cm.
•One diagonal is 48cm.
To find:
•The other diagonal & area of rhombus.
Explanation:
Perimeter of rhombus:
So,
Now,
Area of rhombus:
Thus,
The other diagonal is 14cm &
Area of rhombus is 336cm².
Thank you.
Answer:
ANSWER:-
Given:
•The perimeter of rhombus is 100cm.
•One diagonal is 48cm.
To find:
•The other diagonal & area of rhombus.
Explanation:
Perimeter of rhombus:
= > 2 \sqrt{ {d1}^{2} + {d2}^{2} }=>2
d1
2
+d2
2
So,
\begin{gathered} = > 100 = 2 \sqrt{ {48}^{2} + {d2}^{2} } \\ \\ = > 50 = \sqrt{2304 + {d2}^{2} } \\ [squaring \: both \: sides] \\ \\ = > {50}^{2} = 2304 + {d2}^{2} \\ \\ = > 2500 = 2304 + {d2}^{2} \\ \\ = > {d2}^{2} = 2500 - 2304 \\ \\ = > {d2}^{2} = 196 \\ \\ = > d2 = \sqrt{196} \\ \\ = > d2 = 14cm\end{gathered}=>100=2
48
2
+d2
2
=>50=
2304+d2
2
[squaringbothsides]
=>50
2
=2304+d2
2
=>2500=2304+d2
2
=>d2
2
=2500−2304
=>d2
2
=196
=>d2=
196
=>d2=14cm
Now,
Area of rhombus:
\begin{gathered} = > \frac{1}{2} \times d1 \times d2 \\ \\ = > \frac{1}{2} \times 48cm \times 14cm \\ \\ = > 48cm \: \times 7cm \\ \\ = > 336 {cm}^{2} \end{gathered}1Area of rhombus:
\begin{gathered} = > \frac{1}{2} \times d1 \times d2 \\ \\ = > \frac{1}{2} \times 48cm \times 14cm \\ \\ = > 48cm \: \times 7cm \\ \\ = > 336 {cm}^{2} \end{gathered}
=>
2
1
×d1×d2
=>
2
1
×48cm×14cm
=>48cm×7cm
=>336cm
2
Thus,
The other diagonal is 14cm &
Area of rhombus is 336cm².
Thank you2Area of rhombus:
\begin{gathered} = > \frac{1}{2} \times d1 \times d2 \\ \\ = > \frac{1}{2} \times 48cm \times 14cm \\ \\ = > 48cm \: \times 7cm \\ \\ = > 336 {cm}^{2} \end{gathered}
=>
2
1
×d1×d2
=>
2
1
×48cm×14cm
=>48cm×7cm
=>336cm
2
Thus,
The other diagonal is 14cm &
Area of rhombus is 336cm².
Thank you