The perimeter of rhombus is 104cm and one of its diagonal is 48cm. find the area of rhombus
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Answer:
240cm²
Step-by-step explanation:
Perimeter = 104cm
side = perimeter/4
= 104/4cm
= 26cm
Given diagonal(d₁) = 48cm
Let other diagonal be 'd₂'
A/c to pythagoras theorem,
⇒ (d₁/2)²+(d₂/2)² = side²
⇒ 24² + (d₂/2)² = 26²
⇒ 576 +(d₂/2)² = 676
⇒ (d₂/2)² = 100
⇒ (d₂/2) = 10
⇒ d₂ = 20cm
∵Area of rhombus = 1/2×d₁×d₂
= 1/2×24×20cm²
= 24×10cm²
= 240cm²
Answered by
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area of rhombus is 240 .................
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