Question

the perimeter of rhombus is 20 cm if one of its daigonal is 6 cm then its area is​

Answer 1

Explanation:

let the side of rombhus be s

as we know all the side of rombhus is same

therefore,

s+s+s+s=perimeter

4s=20

s=5cm

as we can se in figure,

diagonal bisect each other at 90

so, by pathogaras theorem,

x^2+3^2=5^2

x^2=25-9

x=4cm

the second digonal is 2x=2*4=8cm

area=product of diagonal/2

area=8*6/2

area=24cm^2

so the area of the the rombhus is 24 cm^2