Question

The perimeter of rhombus is 24cm the measure of its one diagonal is 8cm find its area of rhombus​

Answer 1

Answer:

24cmsquare

Step-by-step explanation:

Let first diagonal be d

Second diagonal be d2

Giver perimeter of a rhombus =20cm

We know perimeter of a rhombus =4 sides

Hence, side =420cm=5cm

Now, we know that the diagonals of a rhombus bisect each other at right angles (90°)

Hence, a right angled triangle can be visualized with side as hypotenuse.

Diagonal length =8cm

Half the length ( since diagonal bisect each other ) =28=4cm

⇒(2d)2+(2d2)2=52

⇒(28)2+(2d2)2=25

⇒42+(2d2)2=25

⇒(2d2)2=25−16

⇒(2d2)2=9