Question

the perimeter of rhombus is 40 cm and the length of one its diagonal is 16 cm find its area​

Answer 1

Answer:

Hi,

First of all we will find length of side of rhombus by using formula

the perimeter of rhombus = 4 * sides

40 = 4 * sides

10 cm = side of rhombus

now we know that diagonal of rhombus are perpendicular bisectors of each other hence by using Pythagoras theorem

(10)squared = (8)squared + (x)squared

6 cm = x

12 cm is length of other diagonal .....(6 * 2)=12 cm

Now area of rhombus = 1/2 * product of length of diagonals

= 1/2 * 16 *12

=96 sq.cm

length of other diagonal is 12 cm and area of rhombus is 96 sq.cm

:)

Answer 2

Answer:

1/2 *12*16

Step-by-step explanation:

perimeter =40cm

side =40/4=10cm

diagonals of a rhombus are perpendicular to each other So,by Pythagoreas

10^2=8^2+x^2

x=6

length of other diagonal =6*2=12

area of rhombus =12*16*1/2

=96 cm^2