Question

the perimeter of rhombus is 40 cm f. one of its diagonal is 16 cm fund the area of the rhombus​

Answer 1

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Answer 2

Plz refers to the attachments

$\bold{Given : }$

• Perimeter of rhombus,P = 40 cm

• One of its diagonal,d1 = 16 cm

$\bold{To \: find \: out : }$

Find the area of given rhombus?

$\bold{Formula \: used : }$

★Perimeter of rhombus = 4 × Side

★Area of rhombus = Base × Height

$\bold{Solution : }$

We know that,

Perimeter of rhombus = 4 × side

➠ 40 = 4 × side

➠ Side = 40/4

➠ Side = 10 cm

By pythagoras therome,

BC² = BD² - CD²

BC² = (16)² - (10)²

BC² = 256 - 100

BC² = 156

BC = 2√39 cm

Now,

Area of rhombus = Base × Height

= 10 × 2√39

= 20√39 cm²

Hence, the area of given rhombus is 20√39 cm.