the perimeter of rhombus is 52 CM if one diagonal is 24 cm find the length of its other diagonal
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3
p=52cm
s=13cm
let the Rhombus be a b c d and the diagonals intersect each other at o.
the diagonals of a Rhombus bisect each other at right angles
therefore,ao=12cm
and ab=13cm
therefore, 12^2 +ob^2=13^2
ob=5cm, bd =10cm
the other diagonal= 10cm
s=13cm
let the Rhombus be a b c d and the diagonals intersect each other at o.
the diagonals of a Rhombus bisect each other at right angles
therefore,ao=12cm
and ab=13cm
therefore, 12^2 +ob^2=13^2
ob=5cm, bd =10cm
the other diagonal= 10cm
Answered by
0
Side of a rhombus= ¼×52cm=13cm
Let AC = 24cm so that
AO= ½×24cm=12cm
∴OB²=AB²−OA²
=(169-144)=25
or OB=5 and thus BD=2.OB=2×5=10cm
Area of the rhombus =
½×24×10
=120cm²
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