Question

the perimeter of rhombus is 52cm and one of its diagonals is 10cm find the length of other diagonal and the area of the rhombus

Answer 1

Perimeter of a rhombus = perimeter of a square =4×side =52cm
=4×side = 52
Side=52÷4= 13 cm
Note: We know that the diagonals of a rhombus bisect each other at right angles.

In right triangle ABC:
OA = ½×AC = ½×10 =5 cm
OB= √AB²-OA²
OB=√(13)²-(5)²
OB=√169-25
OB=√144= 12 cm
BD= ( 2×OB) cm = (2×12) cm = 24 cm
Area of a rhombus= ½× product of its diagonals
= ½× AC×BD = ½×10× 12= 60 cm²

Answer 2

Answer:

Step-by-step explanation: Given below

Perimeter of a rhombus = perimeter of a square =4×side =52cm

=4×side = 52

Side=52÷4= 13 cm

Note: We know that the diagonals of a rhombus bisect each other at right angles.

In right triangle ABC:

OA = ½×AC = ½×10 =5 cm

OB= √AB²-OA²

OB=√(13)²-(5)²

OB=√169-25

OB=√144= 12 cm

BD= ( 2×OB) cm = (2×12) cm = 24 cm

Area of a rhombus= ½× product of its diagonals

= ½× AC×BD = ½×10× 24= 120 cm²

Hope you all understand.

Thank you.

JAI HIND

VIKRAM LANDER PLZ WOKE UP. WHY ARE YOU SLEEPPING; GO ON YOUR MISSION.