Math, asked by raazz8280, 11 months ago

The perimeter of rhombus is the same as that of a rectangle with sides 70cm and 60 cm .If the length of one diagonal of rhombhus is 120cm ,find the length of other diagona

Answers

Answered by shanu6944
19

perimeter of rectangle = perimeter of rhombus

2 (l+b)= 4 a

2 (70+60)= 4 a

2×130=4 a

260= 4 a

a= 260/4

a=65

side^2= (d1/2)^2 + (d2/2)^2

65^2= (120/2)^2 + (d2/2)^2

(65)^2 - (60)^2 = (d2/2)^2

4225 - 3600 = (d2/2)^2

625= (d2/2)^2

root 625=d2/2

25=d2/2

d2=25×2

d2=50cm

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