The perimeter of rhombus is the same as that of a rectangle with sides 70cm and 60 cm .If the length of one diagonal of rhombhus is 120cm ,find the length of other diagona
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perimeter of rectangle = perimeter of rhombus
2 (l+b)= 4 a
2 (70+60)= 4 a
2×130=4 a
260= 4 a
a= 260/4
a=65
side^2= (d1/2)^2 + (d2/2)^2
65^2= (120/2)^2 + (d2/2)^2
(65)^2 - (60)^2 = (d2/2)^2
4225 - 3600 = (d2/2)^2
625= (d2/2)^2
root 625=d2/2
25=d2/2
d2=25×2
d2=50cm
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