the perimeter of right angle triangle is 40 and hypotenuse of 17 find the area of the triangle
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let the sides be a and b
a+b+17 =40
a+b= 27
a2+b2=17^2=289
(a+b)^2=a2 +b2 +2ab
(729-289)÷2 = ab
ab=220
area of triangle is 1/2×a×b=1/2×220=110unit 2
a+b+17 =40
a+b= 27
a2+b2=17^2=289
(a+b)^2=a2 +b2 +2ab
(729-289)÷2 = ab
ab=220
area of triangle is 1/2×a×b=1/2×220=110unit 2
Doubt1:
thanks
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