The perimeter of right angle triangle is 40 c if its hypotenuse is 17 cm find its area
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P+b+h=40
P+b=27
Squaring both sides
P^2+b^2+2pb=729
( using pythagoras theorem)
289 +2pb=729
2pb=440
Pb=220
Therefore area=1/2pb=110 cm^2
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Answer:
P+b+h=40
P+b=27
Squaring both sides
P^2+b^2+2pb=729
( using pythagoras theorem)
289 +2pb=729
2pb=440
Pb=220
Therefore area=1/2pb=110 cm^2
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