Question

the perimeter of right angled triangle is 120 cm and its hypotenuse is 50 cm find the area of triangle
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Answer 1

I think this question is incomplete

Answer 2

$d = 120 \\ r = \frac{120}{2} = > 60 \\ \\ h = 50 \\ \\ by \: \: pythagoras \: \\ theorem \\ \\ {h}^{2} = {p}^{2} + {b}^{2} \\ {50}^{2} = {60}^{2} + {b}^{2} \\ {b}^{2} = {60}^{2} - {50}^{2} \\ {b}^{2} = \: {10}^{2} \\ {b}^{2} = 100 \\ {b}^{2} = \sqrt{100} \\ b = 10 \\ \\ area \: \: of \: \: triangle \: \\ = \frac{1}{2} \times b \times h\\ \\ \frac{1}{2} \times 10 \times 50 \\ \\ = 1 \times 5 \times 50 \\ \\ = 250 \\ \\ so \: \: the \: \: area \: \: of \: \: \\ triangle \: \: is \: 250$