Question

The perimeter of right triangle is 12 cm
it's
hypotenuse is 5 cm find its area​

Answer 1

Step-by-step explanation:

a+b+5=12

a+b=7⇒a=7−b...(1)

a

2

+b

2

=5

2

a

2

+b

2

=25...(2)

From (1) and (2)

(7−b)

2

+b

2

=25

49+b

2

−14b+b

2

=25

2b

2

−14b+24=0

b

2

−7b+12=0

(b−4)(b−3)=0

⇒b=4,3

a=7−b⇒a=3,4

Area=

2

1

×4×3=6sq. units

Here in this triangle a is the length of height and b is the length of base and hypotenuse is of 5 cm. Then we got the value of b as 4 and 3. For the two different values of b we will get two different values of a. Then we can calculate the Area as area = 12×height×base=12(4)(3)=6