The perimeter of right triangle is 30 cm. If the hypotenuse is 13 cm, then what are two sides?
Answers
Answered by
3
2and 3
because the square of 2 and 3 is 4 and 9 respectively.
so,4+9=13
because the square of 2 and 3 is 4 and 9 respectively.
so,4+9=13
yadavpooja82127:
Can you solve it in detail
Please
Answered by
16
Hey Mate
your answer is ---
Let , the two sides be a and b
so, a+b+13 =30
=> a+b = 30-13
=> a+b = 17
=> a = 17-b ...(1)
Now, according to Pythagoras theorem
a^2+b^2 = 13^2
=> (17-b)^2+b^2 = 169
=> 289 + b^2 - 34b + b^2 = 169
=> 2b^2 -34b + 120 = 0
use quadratic formula to solve for b
x = 34 ± √34^2 -4×2×120/4
b = 5 , 12
when , put 5 in equ(1) , we get
a = 17-5
=> a =12
when we put 12 in equ (1), we get
a = 17-12
=> a = 5
Hence, the two sides are 5cm and 12cm
===============
Hope it help you
===============
your answer is ---
Let , the two sides be a and b
so, a+b+13 =30
=> a+b = 30-13
=> a+b = 17
=> a = 17-b ...(1)
Now, according to Pythagoras theorem
a^2+b^2 = 13^2
=> (17-b)^2+b^2 = 169
=> 289 + b^2 - 34b + b^2 = 169
=> 2b^2 -34b + 120 = 0
use quadratic formula to solve for b
x = 34 ± √34^2 -4×2×120/4
b = 5 , 12
when , put 5 in equ(1) , we get
a = 17-5
=> a =12
when we put 12 in equ (1), we get
a = 17-12
=> a = 5
Hence, the two sides are 5cm and 12cm
===============
Hope it help you
===============
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