the perimeter of right triangle is 40 cm and its hypotenuse major 17 cm find the area of the triangle
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Answered by
1
H = 17
B= 40 - 17 /2 = 11.5
P = 11.5
Area = 1/2 x base x height
0.5 x 11.5 x 11.5 = 66.125 cm²
B= 40 - 17 /2 = 11.5
P = 11.5
Area = 1/2 x base x height
0.5 x 11.5 x 11.5 = 66.125 cm²
Answered by
0
Let x + y + z = 40 cm
x + y = 40 - z = 23 cm
x = 23 - y
and x2 + y2 = z2
(23 - y)2 + y2 = 172
529 - 46y + y2 + y2 = 289
2y2 - 46y + 240 = 0
2y2 - 46y + 240 = 0
y = [46 ± √( 2116 - 1920)]/4
y = [46 ± 14]/4 = 15 or 8
x = 8 or 15,
s = semiperiemeter = 40/2 = 20
A = (s(s-x)(s-y)(s-z))1/2 = (20(12)(5)(3))1/2
= 60 cm2
I hope its help u ----------- _____ mark as brainlist plz
x + y = 40 - z = 23 cm
x = 23 - y
and x2 + y2 = z2
(23 - y)2 + y2 = 172
529 - 46y + y2 + y2 = 289
2y2 - 46y + 240 = 0
2y2 - 46y + 240 = 0
y = [46 ± √( 2116 - 1920)]/4
y = [46 ± 14]/4 = 15 or 8
x = 8 or 15,
s = semiperiemeter = 40/2 = 20
A = (s(s-x)(s-y)(s-z))1/2 = (20(12)(5)(3))1/2
= 60 cm2
I hope its help u ----------- _____ mark as brainlist plz
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