The perimeter of rohambus is 20 cm and
one of its daignol is 6 cm long. Find the
length of the other daigonal
cm
Answers
Answered by
5
Step-by-step explanation:
Let a be the side of rhombus
perimeter of rhombus= 20cm
4a =20
a = 5
diagonals of rhombus bisect each other at 90
hypo.²=height²+base²
25=9+base²
4= base
second diagonal is 4+4=8cm
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