Question

the perimeter of rohmbus whose diagonal measure 12cm and 16 cm equal to the perimeter of an isosceles triangle having it's equal sides and the base in the ratio 3:2 then the area of the triangle is​

Answer 1

Step-by-step explanation:

Let ABCD be the rhombus and AC and BD bisect at point O. AC = 16cm and BD = 12cm.

⇒ We know that the diagonals of rhombus bisect at right angles.

⇒ AO=

2

16

=8cm

⇒ BO=

2

12

=6cm

⇒ In right angled △AOB,

By using Pythagoras theorem,

⇒ AB

2

=AO

2

+BO

2

⇒ AB

2

=8

2

+6

2

⇒ AB

2

=64+36

⇒ AB

2

=100

⇒ AB=

100

⇒ AB=10cm

∴ Side of a rhombus is 10cm

Answer 2

Answer:

Answer:area → 50√2

50√2Step-by-step explanation:

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