The perimeter of s right angle triangle is 24 cm. if its hypotenuse is 10 cm. find the area of triangle
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b,p,h
3,4,5( Pythagoras triplet)
multiple of Pythagoras triplet also get Pythagoras triplet
3×2,4×2,5×2
6,8,10
then area= 1/2 ×b×h={6×8}/2=48/2= 24 cm square
3,4,5( Pythagoras triplet)
multiple of Pythagoras triplet also get Pythagoras triplet
3×2,4×2,5×2
6,8,10
then area= 1/2 ×b×h={6×8}/2=48/2= 24 cm square
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