the perimeter of semicircular protestor is 108 cm find the diameter of protector
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perimeter of semicircle =(pie r+2r)
108=22/7 r +
108=22/7 r + 2 r
108= r(22/7+2) (lcm)
108= r(22+14 /7)
108= r(36/7)
108x 7/36=
108x 7/36= r (divided)
21 cm=
21 cm= r
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