the perimeter of sheet of tin in the shape of a quadrant of a circle is 12.5cm find its area
Answers
Answered by
18
perimeter of quadrant=12.5cm
perimeter of quadrant=πr/2+2r
12.5=r(π/2+2)
12.5=r (3.57)
r=3.5cm
area =πr²/4=9.616sq.cm
perimeter of quadrant=πr/2+2r
12.5=r(π/2+2)
12.5=r (3.57)
r=3.5cm
area =πr²/4=9.616sq.cm
Answered by
17
Given:
Circle,
Perimeter = 12.5 cm
To find:
Area
Solution:
By formula,
Area of the quadrant = π * radius^2 / 4
Perimeter of the quadrant = π * radius / 2+ 2 * radius
Substituting,
12.5 = π * radius / 2+ 2 * radius
radius = 3.5
Hence,
Area = 3.14 * ( 3.5 )^2 / 4
Area = 9.6 sq.cm
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