Question

the perimeter of square 68cm Nd 60cm find the perimeter od third sq. whoose area is equal to the difference of the area of two squares​

Answer 1

4a1=68

a1=17

4a2=60

a2=15

difference of the area of these two square is equal to third squares area

(17^2-15^2)

(289-225)

64

(a3)^2=64

a3=8

so perimeter of third square is

4×8

32cm Ans

Answer 2

bro answer is 32 CM

hope it helped u