the perimeter of square 80cm . find the perimeter of the perimeter of the square whose side is equal to the diagonal of the given square.
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Answer:
Perimeter of rectangle = perimeter of square =80 cm
⇒2(l+b)=45=80
⇒S= 80/4 =20 cm;2(l+b)=80
⇒l+b=40 cm - (1)
difference m areas = 100 cm2
5^2−(lb)=100
(20)(20)−(lb)=100
⇒lb=300 - (2)
From (1) and (2)
30+10=40;3×10=l×b
⇒l=30 and b=10
sides of rectangle are 30,10 cm
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⇒2(l+b)=45=80
⇒S= 80/4 =20 cm;2(l+b)=80
⇒l+b=40 cm - (1)
difference m areas = 100 cm2
5^2−(lb)=100
(20)(20)−(lb)=100
⇒lb=300 - (2)
From (1) and (2)
30+10=40;3×10=l×b
⇒l=30 and b=10
sides of rectangle are 30,10 cm
Answer: 20cm
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