Math, asked by omairjoker, 3 months ago


The perimeter of square field is 56 m. Find the side of this square,
The norimotor of square field is 200 m. Find the side of this field .​

Answers

Answered by irshikeshps
1

Answer:

4* side=56

side=56/4=14

Step-by-step explanation:

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Answered by mayajakhar79
1

Solution:-

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࿊ Here both the questions has given us the perimeter of the square field. We will consider the side as x and will find the answer applying the formula of perimeter of square.

SOLUTION OF QUES 1

ANSWER:-

✓ Side of the square is 14 m.

GIVEN:-

⍆ Perimeter of the square field = 56 m

TO FIND:-

➮ Side of the square field = ?

FORMULA:-

✩ Perimeter of square = 4 × Side

SOLVING BY APPLYING THE FORMULA:-

⍆ Perimeter of the square field = 56 m

✩ Perimeter of square = 4 × Side

Let the side be x.

  • Finding the side:-

 \leadsto \tt{56 \: m = 4 \times x}

 \leadsto \tt{56 \: m = 4x}

 \leadsto \tt{ \dfrac{56}{4} \: m= x}

 \leadsto \tt{ \dfrac{ \not{56}}{ \not{4}} \: m= x}

 \leadsto \tt{{14} \: m= x}

 \leadsto \tt{x = 14 \: m}

The side of the square is 14 m.

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SOLUTION OF QUES 2

ANSWER:-

✓ Side of the square is 50 m.

GIVEN:-

⍆ Perimeter of the square field = 200 m

TO FIND:-

➮ Side of the square field = ?

FORMULA:-

✩ Perimeter of square = 4 × Side

SOLVING BY APPLYING THE FORMULA:-

⍆ Perimeter of the square field = 200 m

✩ Perimeter of square = 4 × Side

Let the side be x.

  • Finding the side:-

 \leadsto \tt{200 \: m = 4 \times x}

 \leadsto \tt{200\: m = 4x}

 \leadsto \tt{ \dfrac{200}{4} \: m= x}

 \leadsto \tt{ \dfrac{ \not{200}}{ \not{4}} \: m= x}

 \leadsto \tt{{50} \: m= x}

 \leadsto \tt{x = 50 \: m}

The side of the square is 50 m.

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