Question

The perimeter of square field is numerically equal to its area. Find each side of the square

Answer 1

Hence, each side of the square is 4(unit)².

Answer 2

$\huge \sf \underline \red{Answer : }$

$\sf \underline \green{ \therefore \: a = 4}$

$\sf \underline \green{ \therefore \: Area \: of \: square = {a}^{2} = 4 \times 4 = 16}$

$\sf \huge \underline \pink{To \: find : }$

• Each side of the square

$\huge \sf \underline \blue{Solution : }$

$\sf \underline{Given : }$

• The perimeter of square field is numerically equal to its area.

$\sf \underline{so, \: we \: know \: that : }$

$\: \: \: \: \: \: \: \: \: \star \: \sf \underline{perimeter \: of \: square = 4a}$

$\: \: \: \: \: \: \: \: \: \star \: \sf \underline{area\: of \: square = {a}^{2} }$

• so now we have to compare perimeter and area of square we get,

$\: \: \: \: \: \: \: \: \: \: \: \: \implies \sf{4a = {a}^{2}}$

$\: \: \: \: \: \: \: \: \: \: \: \: \implies \sf{ \dfrac{ {a}^{2} }{4} = 4 }$

$\: \: \: \: \: \: \: \: \: \: \: \: \implies \sf{a = 4}$

$\sf \underline \green{ \therefore \: a = 4}$

$\sf \underline \green{ \therefore \: Area \: of \: square = {a}^{2} = 4 \times 4 = 16}$