Question

the perimeter of square is 40 find its diogonal.
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Answer 1

$\huge\mathfrak{(✷Answer✯)}$

Perimeter of square = 4 × side

Diagonal of perimeter = $d = \sqrt{2} \frac{p}{4} = {\sqrt{2.} \frac{40}{4}≈} \: {14.14 }$

${\therefore \: d ≈ 14.14}$

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