Question

The perimeter of square is (4x+8) what will be the area

Answer 1

P=4x+8

P=2(l+b)

4x+8=2(l+b)

2(2x+4)=2(l+b)

{2(2x+4)/2=(l+b)

2x+4=(l+b)

So, L=2x. and b = 4

Area of square=L×B

=2x×4

=8x

Answer 2

Answer:

$x^2 + 4x + 4$

Step-by-step explanation:

According to the question,

We know that all sides of the square are equal in measure.

And the perimeter is the sum of all sides.

Given, Perimeter = 4x+8

let the sides of the square be $a$.

The perimeter of the square is $4a$.

Then,

$4a = 4x+8\\\\a = \frac{4x+8}{4} \\\\a = x + 2$

We get $a = x + 2$

And we know that Area of the square = $a^2$.

Area of the square

$= a^2 = (x + 2)^2\\\\\\= x^2 + 4x + 4$

Hence, the Area of the square is $x^2 + 4x + 4$.