The perimeter of square is 56 metre.The area of rectangle is 8 sq.m. less than the area of given. If the length of the rectangle 16 m,find the breadth.
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Answer:
Let the side of square be a
perimeter of Square =4a
Given perimeter=56m
∴4a=56
a=14m
Area of square=(14m) ²
=196 sq.m
Area of rectangle=Area of square−8
=196−8=188 sq.m
Let the length of rectangle be 'l'
breadth be 'b'
Given l=16m
Area of rectangle=lb=188
⇒16b=188
b= 188/16
b= 47/4 m
∴ Breadth of rectangle= 47 /4 m.
Explanation:
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Explanation:
Perimeter of Rectangle= 2* (L+B)
56 meter= 2*(16m+B)
56meter/2= (16m+B)
28= (16m+B)
28-16= B
12 = Breadth
Checking
Perimeter of Rectangle= 2* (L+B)
= 2*(16m+12m)
= 2*(28)
Perimeter = 56 m
Hope it Helps
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