Question

the perimeter of square is 64 the area of a rectangle is 6 metre 2 less than the area of the square given if the length of the rectangle is 25 metre find its breadth​

Answer 1

Answer:

Breadth of this rectangle is 10 m.

Step-by-step explanation:

Here,

Perimeter of a square is 64 metre { unit for the perimeter of the square is not mentioned.Here, it is taken as metre }

From the properties of squares :

• Perimeter of square : 4 x length of side
• Area of square : side^2 or side x side

Here,

= > Perimeter of square = 64 m

= > 4 x length of side of this square = 64 m

= > length of side of this square = 64 m / 4 or 16 m

Thus,

= > Area of this square = ( 16 m )^2

= > Area of this square = 256 m^2

Given,

Area of rectangle is 6 metre^2 less than the area of the square.

Also,

Length of the rectangle is 25 metre.

From the properties of rectangle :

• Area of rectangle is the product of lengths of its length and breadth.

According to this question :

= > Area of rectangle = area of square - 6 m^2

= > length of rectangle x breadth of rectangle = 256 m^2 - 6 m^2

= > 25 m x breadth of rectangle = 250 m^2

= > Breadth of rectangle = ( 250 m^2 ) / 25m = 10 m

Hence the breadth of this rectangle is 10 m.

Looking for a short solution ?

According to the question :

= > Perimeter of square = 64 m

= > 4 x side of square = 64 m

= > side of square = 16 m

So, area of square should be ( 16 m )^2 or 256 m^2

Given,

= > area of rectangle = area of square - 6 m^2

= > 25 m x breadth = 256 m^2 - 6 m^2

= > Breadth of rectangle = 250 m^2 / 25 m = 10 m

Hence the breadth of this rectangle is 10 m.

Answer 2

Step-by-step explanation:

area of rectangle

is

equa

to

10

cm 2