Question

The perimeter of square JKLM is 48 units.



What is the value of x?

6
9
12
15

Answer 1

It is known that, the perimeter of any square is equal to P=4b where b can be referred as the length side of that square.

In the problem, we can see b=(x+3) units and P=48 units.

By substituting the given formula, we can write 48=4(x+3).

Therefore, we can write 12 = x +3 or, x = 12-3 = 9 units.

Hence the value of x is 9 units.