Math, asked by manish67214, 10 months ago

The perimeter of squere is double that of a rectangle . If perimeter of the square is 120m and length an breadth of the rectangle are in the ratio 3:2, find the lenght and breadth of the rectangle​

Answers

Answered by SparklingBoy
34

Answer:

Given that perimeter of the square is double the perimeter of rectangle.

Also,

given that perimeter of square is 120 m

So, perimeter of rectangle = 120/2

perimeter of rectangle = 120/2= 60m.

And length and breadth of the rectangle are given in the ratio

3:2.

Now ,

let

length of rectangle(l) = 3x

and

breadth of rectangle(b)=2x.

Now,

we know that perimeter of rectangle = 2(l + b)

So,

2(3x + 2x) = 60

⟹ 2 × 5x = 60

⟹10x = 60

x= 6.

So,

length = 3x = 3 × 6 = 18m.

length = 3x = 3 × 6 = 18m.breadth = 2x = 2 × 6 = 12m.

Answered by VishalSharma01
72

Answer:

Step-by-step explanation:

Given :-

The perimeter of squere is double that of a rectangle.

To Find :-

length and breadth of the rectangle​.

Solution :-

Let the length of rectangle be 3x .

And the breadth of rectangle be 2x.

According to the Question,

Perimeter of square = 2 perimeter of rectangle

⇒  120 = 2 [2 ( l + b )]

⇒  60 = 2 ( 3x + 2x )

⇒  30 = 5x

⇒  x = 30/5

⇒ x = 6

Length = 3x = 18 m

Breadth = 2x  = 12 m

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