the perimeter of the 4 triangle is 8 +13a +7a sq and two of its sides are 2a sq+3a+2and 3a sq _4a _1 find the third side of the triangle
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8+13a+7a²=2a²+3a+2+3a²-4a-1+x
8+13a+7a²=5a²-a-3+x
8+3+13a+a+7a²-5a²=x
x=11+14a+2a²
8+13a+7a²=5a²-a-3+x
8+3+13a+a+7a²-5a²=x
x=11+14a+2a²
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